5-1/t-4/t^2=0

Solution for 5-1/t-4/t^2=0 equation:

D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

5-(1/t)-(4/(t^2)) = 0

5-t^-1-4*t^-2 = 0

t_1 = t^-1

5-4*t_1^2-1*t_1^1 = 0

5-4*t_1^2-t_1 = 0

DELTA = (-1)^2-(-4*4*5)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+1)/(-4*2) or t_1 = (1-81^(1/2))/(-4*2)

t_1 = -5/4 or t_1 = 1

t_1 = -5/4

t^-1+5/4 = 0

1*t^-1 = -5/4 // : 1

t^-1 = -5/4

-1 < 0

1/(t^1) = -5/4 // * t^1

1 = -5/4*t^1 // : -5/4

-4/5 = t^1

t = -4/5

t_1 = 1

t^-1-1 = 0

1*t^-1 = 1 // : 1

t^-1 = 1

-1 < 0

1/(t^1) = 1 // * t^1

1 = 1*t^1 // : 1

1 = t^1

t = 1

t in { -4/5, 1 }